Question

Find the value of discriminant for the following equation. 2y²-y-2=0 *

2 points


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Answer 1

Step-by-step explanation:

discriminant (D)=b^2-4ac

=-1^2-4×2×[-2)

=1-8×[-2)

=1+16

=17

Answer 2

Answer:

2y²- y - 2 = 0

a = 2 , b = -1 , c = -2

∆ = b²- 4ac

= (-1)² - 4(2)-2

= 1 + 16

∆ = 17

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