Find the value of discriminant for the following equation. 2y²-y-2=0 *
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Answered by
0
Step-by-step explanation:
discriminant (D)=b^2-4ac
=-1^2-4×2×[-2)
=1-8×[-2)
=1+16
=17
Answered by
3
Answer:
2y²- y - 2 = 0
a = 2 , b = -1 , c = -2
∆ = b²- 4ac
= (-1)² - 4(2)-2
= 1 + 16
∆ = 17
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