Question

find the value of discriminant for the following equation 2ysquare-y+2=0

Answer 1

-y+2=0
-y=-2 as we will transfer +2 to the RHS then it will become -2
y=2 as we will cancel the both - and - so it will become plus (+)

Answer 2

$a \: = 2 \: \: b = - 1 \: \: c = 2$

$d = \sqrt{b {}^{2} - 4ac }$

$d = \sqrt{( - 1) {}^{2} - 4(2)(2)}$

$d = \sqrt{1 - 16} = \sqrt{ - 15}$



Thanks