find the value of discriminant for x2 +x - 20 =0
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Answer:
The solutions for the equation are: x=−4,x=5
Explanation:
x2−x−20=0
The equation is of the form ax2+bx+c=0 where:
a=1,b=−1,c=−20
The Discriminant is given by:
Δ=b2−4⋅a⋅c
=(−1)2−(4⋅1⋅(−20))
=1+80=81
The solutions are found using the formula:
x=−b±√Δ2⋅a
x=−(−1)±√812⋅1=1±92
x=1+92=102,x=5
x=1−92=−82,x=−4
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