Question

Find the value of discriminant of each of the following equations. I)x²+4x+1=0​

Answer 1

EXPLANATION.

Quadratic equation.

⇒ x² + 4x + 1 = 0.

As we know that,

⇒ D = Discriminant  Or b² - 4ac.

⇒ D = (4)² - 4(1)(1).

⇒ D = 16 - 4.

⇒ D = 12.

                                                                                                                           

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and different, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or Complex conjugate.

Answer 2

Answer:

12

Step-by-step explanation:

Given :-

x² + 4x + 1 = 0

To find :-

Value of discriminant

Solution :-

Discriminant = b² - 4ac

Comparing to quadratic equation,

• ax² + bx + c = 0

We get,

• a - 1

• b - 4

• c - 1

Substituting in discriminant formula,

• (4)² - 4(1)(1)

• 16 - 4

• 12

∴ The discriminant is greater than 0, so the roots are real and different.