find the value of discriminant of quadratic equation 2x2-5x-12=0
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Answered by
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2x2-8x+3x-12
2x (x-4)+3 (x-4)
(x-4)(2x+3)
x=4 or x=-3/2
2x (x-4)+3 (x-4)
(x-4)(2x+3)
x=4 or x=-3/2
Thatsomeone:
asker asked for discriminant not solution
Answered by
10
a = 2
b = - 5
c = -12
discriminant = b^2 - 4ac
= ( - 5 )^2 - 4 ( -5 )( -12 )
= 25 - 240
= - 215
b = - 5
c = -12
discriminant = b^2 - 4ac
= ( - 5 )^2 - 4 ( -5 )( -12 )
= 25 - 240
= - 215
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