Question

find the value of discriminant of quadratic equation (x-a)(x-b)=c^2.......
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help me guys..​

Answer 1

Step-by-step explanation:

Expand (x - a)(x - b) = c2 and get

x2 - bx - ax + ab = c2

Group like terms and get

x2 - (b + a)x + (ab - c2) = 0

Note this is an equation of the form

Ax2 + Bx + C = 0,

which is a quadratic equation, with

where A = 1, B = -(b + a), and C = ab - c2

Its solution is

x = [-B ± √(B2 - 4AC)] / (2A)

This gives at most 2 different solutions if the argument of the square root is not zero.

Answer 2

Step-by-step explanation:

Expand (x - a)(x - b) = c2 and get

x2 - bx - ax + ab = c2

Group like terms and get

x2 - (b + a)x + (ab - c2) = 0

Note this is an equation of the form

Ax2 + Bx + C = 0,

which is a quadratic equation, with

where A = 1, B = -(b + a), and C = ab - c2

Its solution is

x = [-B ± √(B2 - 4AC)] / (2A)

This gives at most 2 different solutions if the argument of the square root is not zero.