Question

Find the value of discriminant of tha quadratic equation : 3x²+10x-8=0

Answer 1

Explanation:

D=b²-4ac

10)²-4*3*(-8)

100+96=196

[tex]x = - b + - \sqrt{d} \div 2a \\ - 10 + - \sqrt{196} \div 2 \times 3 \\ - 10 + 14 \div 6 \\ 4 \div 6 \\ 2 \div 3

Answer 2

Answer:

D = 196

Explanation:

D = b² - 4ac

Here in this equation,

a = 3 ; b = 10 ; c = -8

Hence,

D = (10)² - 4(3)(-8)

= 100 + 96

= 196