Question

Find the value of discriminant of the equation √3 x²+ 2√3 x + √3 = 0

Answer 1

Solution :-

We know that, If A•x^2 + B•x + C = 0 ,is any quadratic equation, then its discriminant is given by;

• D = B^2 - 4•A•C

So, comparing given quadratic equation √3 x²+ 2√3 x + √3 = 0 with A•x^2 + B•x + C = 0 we get ,

• A = √3
• B = 2√3
• C = √3

then, putting values we get,

→ D = B² - 4AC

→ D = (2√3)² - 4 * √3 * √3

→ D = (2)²(√3)² - 4(√3)²

→ D = 4 * 3 - 4 * 3

→ D = 12 - 12

→ D = 0 (Ans.)

Hence, the value of discriminant of the given equation is equal to zero .

Extra knowledge :-

• If D = 0 , then the given quadratic equation has real and equal roots.

• If D > 0 , then the given quadratic equation has real and distinct roots.

• If D < 0 , then the given quadratic equation has unreal (imaginary) roots.

Learn more :-

solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method

https://brainly.in/question/18828734

Answer 2

HELLO DEAR,

GIVEN:- Find the value of discriminant of the equation √3 x²+ 2√3 x + √3 = 0

SOLUTION:-

The given equation is

√3x² + 2√3 x + √3 = 0

where ,

a = √3, b = 2√3 , c = √3

And Discriminant (D) = b²-4ac

So, D = (2√3)² - 4√3√3

D = 4×3 - 4×3

D = 12 - 12

D = 0

Therefore, the discriminant of the equation √3x² + 2√3 x + √3 = 0

is zero.

THANKS.