Question

find the value of discriminant of the following equation ​

Answer 1

Answer:

here,

a=5,b=-1,c=0

b^2-4ac= -1^2-4×5×0

=1-20×0

=1-0

= -1

Answer 2

m -5m= -3

m-5m+3

(m-3) (m+1)

m-3=0 m+1=0

m=3=d m= -1=b

sum of the zeroes =r+b

=3+(-1)=3-1=2,,,

protect of the zeroes=rb=3*(-1)=-3,,