Question

Find the value of discriminant of the quadratic equation x2+4x+4=0​

Answer 1

x2+2x+2x+4=0

x(x+2)+2(x+2)

x =-2 x =-2

Answer 2

Answer:

x² + 4x + 4 = 0

Here a = 1 , b = 4 & c = 4

As D = b² - 4ac

D = 16 - 4 × 1 × 4

D = 16 - 16 = 0

So, the equation have two equal real roots exist.

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