Find the value of Dx for the simultaneous equation 6x- 3y = - 10 and 3x+5y-8=0 ?
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6x- 3y= -10 .....(i)
3x+5y= 8 .......(ii)
on multiplying the equation (ii) by 2 on both sides
we have:
6x+10y = 16.....(iii)
Now(iii) - (i)
i.e.,6x+10y= 16
6x- 3y = -10
- + +
_______________
13y= 26
y= 2
On putting the value of y in equation (i)
i.e., 6x-3(2) = -10
6x= -10+6
x= -4/6= -2/3
Thus, x= -2/3
& y= 2
Note: This question is solved by using Elimination method.
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