Question

find the value of dy/dt at t=0, if y=3sin2x and x = t²+π​

Answer 1

Answer:

t=0,if y=3sin2x=tbitwin the people in the value is=t square 3 pai r square

Answer 2

Answer:

y = 3 sin2x

x = $t^{2}$ + π

$\frac{dy}{dx} =$ 6 cos2x

$\frac{dx}{dt}$ = 2t

now

$\frac{dy}{dt}$ =$\frac{6cos2x}{2t}$

Explanation: