Question

Find the value of dy/dx if y= x^x​

Answer 1

Answer:

the value of d is 1x-2

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Answer 2

"We have, y=${x}^{x}$

Taking log on both the sides, we get

log y = x log x

On differentiating w.r.t. x, we get

1/y × dy/dx = x/x +logx

⇒ dy/dd = y + ylogx

⇒ dy/dx = ${x}^{x}$ (1+logx) ....(∵y = ${x}^{x}$ )

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