Question

Find the value of each angles if
x, (2x +13), (3x + 10) and (x-6) are
all the angles of a quadrilateral.
a​

Answer 1

Step-by-step explanation:

Given:-

x, (2x +13), (3x + 10) and (x-6) are all the angles of a quadrilateral.

To find:-

Find the value of each angles.

Solution:-

Given angles of a quadrilateral are x, (2x +13), (3x + 10) and (x-6)

We know that

'The sum of all angles in a quadrilateral is equal to 360°'

x+2x+13+3x+10+x-6=360°

=>7x+17=360°

=>7x=360°-17

=>7x=343°

=>x=343/7

=>x=49°

Now

2x+13=2(49)+13=98+13=111°

3x+10=3(49)+10=147+10=157°

x-6=49-6=43°

Answer:-

The angles of the quadrilateral are 49°,111°,157°,43°

Used formulae:-

The sum of all angles in a quadrilateral is equal to 360°