find the value of each of the following
81^3 - 80^3
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recall that 81=9*9=(3^2)*(3^2)=3^(2+2)=3^4 so 1/81=1/(3^4)=3^(-4) so 3^x=3^(-4) would be ... If 4^x+2(2^x) =80, what is the value of x?
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this is your answer
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hlo I because he yr if all is so if so if
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