find the value of each of the following by using column method 34 ki power 2
Answers
Step-by-step explanation:
xjxjdjdjdhdjdududididjfjdudududidususdjdizixkfifo&prhrnthdhegwhehshhdjsjsjgjfrjfjvjxjd g c dcsobiwzgiagxazhqixb
. Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
(i) 25
(ii) 37
(iii) 54
(iv) 71
(v) 96
Solution:
(i) 25
So here, a = 2 and b = 5
Column I Column II Column III
a2
4
+2
6
2ab
20
+2
22
b2
25
6 2 5
∴ 252 = 625
Where, it can be expressed as
252 = 25× 25 = 625
(ii) 37
So here, a = 3 and b = 7
Column I Column II Column III
a2
9
+4
13
2ab
42
+4
46
b2
49
13 6 9
∴ 372 = 1369
Where, it can be expressed as
252 = 37× 37 = 1369
(iii) 54
So here, a = 5 and b = 4
Column I Column II Column III
a2
25
+4
29
2ab
40
+1
41
b2
16
29 1 6
∴ 542 = 2916
Where, it can be expressed as
542 = 54 × 54 = 2916
(iv) 71
So here, a = 7 and b = 1
Column I Column II Column III
a2
49
+1
50
2ab
14
+0
14
b2
01
50 4 1
∴ 712 = 5041
Where, it can be expressed as
712 = 71 × 71 = 5041
(v) 96
So here, a = 9 and b = 6
Column I Column II Column III
a2
81
+11
92
2ab
108
+3
111
b2
36
92 1 6
∴ 962 = 9216
Where, it can be expressed as
962 = 96 × 96 = 9216