Question

find the value of each of the following polynomial s at the point x=0, -3and 1/2 when 2x²+x+1​

Answer 1

Step-by-step explanation:

1) 2(0) ^2+0+1 (by 0)

2(0)+1

0+1

1

2) 2(-3)^2+(-3) +1 (by -3)

2(9) -3+1

18-2

16

3) 2(1/2) ^2+1/2+1 (by 1/2)

2(1/4) +1/2+1

2/4+1/2+1

1/2+1/2+1

1+1+2/2 (1+1+2 the whole by 2)

4/2

2

Answer 2

Answer:

at x=0, value is 1

at x=-3, value is 16

at x=1/2, value is 2

Step-by-step explanation:

2x²+x+1

at x=0

• =2(0)²+(0)+1
• =1

at x=-3

• =2(-3)²+(-3)+1
• =2(9)-3+1
• =18-2
• =16

at x=1/2

• =2(1/2)²+(1/2)+1
• = 2(1/4)+(1/2)+1
• =1/2+1/2+1
• =2