Find the value of each of the following polynomials for the indicated value of
waruble
(*) - 4r? - 3x + 7 at
012 - 4y + vit aty=1
no at +31-26atroprer
p() = 32.5-71
q(57'4+ Vitr2
Now consider the polynomial r(t) = 1-1
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Answer:
(i) p(x)=4x²-3x+7.
x=1.
p(1)=4(1)²-3(1)+7.
=4(1)-3+7.
=4-3+7.
=1+7. (Because +×-=- & largest number is impprtant).
=8.
(ii) q(y)=2y³-4y+√11.
y=1.
q(1)=2(1)³-4(1)+√11.
=2(1)-4+√11.
=2-4+√11.
=-2+√11. (Because +×-=- & largest number is impprtant).
(iv) s(z)=z³-1.
z=1.
s(z)=(1)³-1.
=1-1.
=0. (Because +×-=-).
(v) p(x)=3x²+5x-7.
x=1.
p(1)=3(1)²+5(1)-7.
=3(1)+5-7.
=3+5-7.
=8-7.
=1. (Because +×-=- & largest number is impprtant).
(vi) q(z)=5z³-4z+√2.
z=2.
q(2)=5(2)³-4(2)+√2.
=5(8)-4+√2.
=40-4+√2.
=36+√2. (Because +×-=- & largest number is impprtant).
Sorry I didn't understand (iii) question.
I think this is your answer.
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