Find the value of each of the following without actual addition. (a) 1+3+5+7+9+11+13+15+17+19+21+23+25
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i.e. 121 = 1+3+5+7+9+11+13+15+17+19+21. Thus , 121 is a perfact square. Since, 55 cannot be expressed as the sum of successive old numbers starting from 1.
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