Find the value of each the following polynomial for the indicated value of variable r(t)=4t⁴+3t-t²+6 at t=p,t belongs r
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Answer:
r (p) = 4p⁴ + 3p - p² + 6
Step-by-step explanation:
r (t) = 4t⁴ + 3t - t² + 6
Putting t = p
r (p) = 4p⁴ + 3p - p² + 6
Hence, the value of the given polynomial with t = p is
r (p) = 4p⁴ + 3p - p² + 6
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