Find the value of Ecell of electrochemical cell Zn / Zn+2(0.6) || Cd+2 (0.85) /Cd E°zn+2/Zn= -0.16V E°cd+2/Cd =-0.40V
Answers
Answered by
3
Step-by-step explanation:
ecell =e cathode -e anode
=-016-0.40=-0.56V OK friend
Answered by
3
Answer:
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