find the value of EF
Attachments:
Answers
Answered by
0
Given : a rectangle from center of circle with dimensions
To find : Value of EF
Soluion:
Rectangle has sides 15 & 20
=> Diagonal length = BD = OC = √(15² + 20²) = 25
=> Radius of circle = OC = 25
BD = 25
let draw OM ⊥ EF (or BD)
Let say DM = x then BM = 25 - x
then OM² = OD² - DM²
=> OM² = 15² - x²
=> OM² = 225 - x²
& OM² = OB² - BM²
=> OM² = 20² - (25 - x)²
=> OM² = 400 - ( 625 + x² - 50x)
=> OM² = -225 - x² + 50x
225 - x² = -225 - x² + 50x
=> 50x = 450
=> x = 9
OM² = 225 - 9²
=> OM² = 144
=>OM = 12
OM = 12 OE = OF = 25 ( Radius)
=> EM² = FM² = 25² - 12²
=> EM = FM = √481
=> EF = 2√481 = 43.86
EF = 2√481 = 43.86
Learn more:
In a circle of radius 10 cm , PQ and PR are two chords such that PQ ...
https://brainly.in/question/7926216
Similar questions