Question

find the value of even +odd+even+........+odd(20 times)​

Answer 1

Step-by-step explanation:

even

I thing it's correct

Answer 2

Answer:

The sum will be even.

Step-by-step explanation:

So there are 20 numbers in the given series.

Out of the twenty numbers, ten are odd and ten are even numbers.

Let us denote even numbers as 2n and odd numbers as 2n+1

So the sum can be denotes as the summation of all the odd numbers and even numbers.

Or,

Sum = 10(2n) + 10(2n+1)

So as you can see when we multiply odd numbers (2n+1) with ten, it becomes even.

10(2n+1) = 5(2(2n+1)) Which is nothing but 5 times an even number which is even.

So we can conclude that the sum will be even too.

Project code #SPJ2