find the value of expansion when n=2n^5+5n²+3n-4
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Putting n=1, 5n
2
−3n
=5−3=2
putting n=2, 5n
2
−3n
5×2
2
−3×2 =14
therefore 2nd term is 14−2=12
therefore A.P is 2,12,22.... and so on.
10th term =a+9d
=2+9×10
=2+90
=92.
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