Question

Find the value of expression (81x² + 16y² - 72xy), when x = 2/3 and y = 3/4.

Answer 1

Answer:

9

Step-by-step explanation:

hope it will help u....

Answer 2

9 is the  expression value (81x² + 16y² - 72xy), when x = 2/3 and y = 3/4.

Step-by-step explanation:

Given, x= 2/3 and y= 3/4

To find the value of the given equation,

$81x^{2}+16y^{2} -72x$

Put the value of x=2/3 and y= 3/4 in the equation.

$=81$×$(2/3)^{2} +16$×$(3/4)^{2}$-72×2/3×3/4

=81×4/9 +16×9/16-72/2

=324/9+144/16-36

=36+9-36

9

Hence, $81x^{2} +16y^{2} -72xy=9$

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