find the value of expression (x+y) ^2-7xy -8y^2 , when x=3 and y=4
iska answer -163 hona chahiye
solution bta do plzzzzz
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2
Answer:
-163
Step-by-step explanation:
=(x+y)^2-7xy-8y^2
=(3+4)^2-7×3×4-8×4^2
=49-84-128
=. -163
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(x+y)²-7xy -8y²
where x= 3 and y= 4
(3+4)²-7×3×4 -8×4²
7² -84 - 128
49 -84 - 128
49- 212
-163
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