find the value of expression y^2+2xy+3x^2y, when x=1, y=1
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Step-by-step explanation:
GIVEN : Expression = y² + 2xy + 3x²y x= 1 y = 1
substuting x = 1 and y = 1 in the given expression....
=》 (1)² + 2(1)(1) + 3(1)²(1)
=》 1 + 2 + 3
=》 6
HENCE , THE VALUE OF GIVEN EXPRESSION IS = 6
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