Question

Find the value of following

2cos67°/sin23° - tan40°/cot50° - cos0°​

Answer 1

✬ Value = 0 ✬

Step-by-step explanation:

Given:

• 2cos67°/sin23° – tan40°/cot50° – cos0°

To Find:

• Value ?

Solution: Identities to be used here

• cos(90° – θ) = sinθ

• tan(90° – θ) = cotθ

• cos0° = 1

$\implies \: \frac{2cos(90 - 23)\degree}{sin23\degree} \: - \frac{tan(90 - 50)\degree}{cot50\degree} \: - cos0\degree \\ \\ \implies \: \frac{2sin23\degree}{sin23\degree} \: - \frac{cot50\degree}{cot50\degree} \: - cos0\degree \\ \\ \implies \: 2 - 1 - 1 \\ \\ \implies2 - 2 \\ \\ \implies0$

Hence, value of given expression will be 0.

Answer 2

$\boxed{\purple{\rm{ \frac{ 2cos67°}{sin23°} - \frac{tan40°}{cot50°} - cos0\degree }}}$

$⇢\rm \frac{2cos(90°-23°)}{sin23°} -\frac{tan(90° - 40°)}{cot 50°} - cos 0°$

$⇢\rm \frac{ 2sin23°}{sin23°} - \frac{cot50°}{cot50°} -cos0°$

$⇢\rm 2 - 1 - 1$

$⇢\rm 2 - 2$

$\therefore~\red{\rm{ 0}}$