Math, asked by sunil4460, 11 months ago

Find the value of following data is 21.6, Find the value of p

Xi=6,12,18,24,30,36 and Fi=5,4,p,6.4,6

Answers

Answered by Anonymous
23

AnswEr :

\begin{tabular}{| c | c | c | c | c | c | c |}\cline{1-7}</p><p>\bf{xi} &amp; \sf{6} &amp; \sf{12} &amp; \sf{18}  &amp; \sf{24} &amp; \sf{30} &amp; \sf{36}\\ \cline{1-7}\bf{fi} &amp; \sf{5} &amp; \sf{4} &amp; \sf{p} &amp; \sf{6} &amp; \sf{4} &amp; \sf{6}\\ \cline{1-7} \end{tabular}

 \rule{100}1

\begin{tabular}{| c | c | c | }\cline{1-3}</p><p>\bf{xi} &amp; \bf{fi} &amp; \bf{fixi}\\ \cline{1-3}\sf{6} &amp; \sf{5} &amp; \sf{30}\\ \cline{1-3}\sf{12} &amp; \sf{4} &amp; \sf{48}\\ \cline{1-3}\sf{18} &amp; \sf{p} &amp; \sf{18p}\\ \cline{1-3}\sf{24} &amp; \sf{6} &amp; \sf{144}\\ \cline{1-3}\sf{30} &amp; \sf{4} &amp; \sf{120}\\ \cline{1-3}\sf{36} &amp; \sf{6} &amp; \sf{216}\\ \cline{1-3}\sf{Total  } &amp; $\sum\limits\sf\ fi \sf\ = 25 +p$ &amp;$\sum\limits\sf\ fixi \sf\ = 558 + 18p$\\ \cline{1-3} \end{tabular}

 \rule{200}2

\normalsize\star{\boxed{\sf{Mean \left( \bar{x} \right) = \frac{\sum\limits\ f_i x_i}{\sum\limits\ f_i} }}}

\normalsize\dashrightarrow\sf\ 21.6  = \frac{558 + 18p}{25 + p}

\scriptsize\sf{ \: \: \: \: \: \: \: \: \: \dag\ Cross \: multiplication}

\normalsize\dashrightarrow\sf\ 21.6(25 + p)   = 558 + 18p

\normalsize\dashrightarrow\sf\ 540 + 21.6p  = 558 + 18p

\normalsize\dashrightarrow\sf\ 558 - 540 = 21.6p - 18p

\normalsize\dashrightarrow\sf\ 18 = 3.6p

\normalsize\dashrightarrow\sf\ p = \frac{18}{3.6}

\normalsize\dashrightarrow\sf\ p = \frac{180}{36}

\normalsize\dashrightarrow\sf\ p = 5

\therefore\:\underline{\textsf{Hence, \: the \: value \: of \: p \: is}{\textbf{\: \: 5 }}}


Anonymous: Good
Answered by Anonymous
8

\Huge\mathrm{Question: }

⟶ Find the value of p when the mean of the Following data is 21.6 .

Xi = 6 , 12 , 18 , 24 , 30 , 36

Fi = 5 , 4 , p , 6 , 4 , 6

\Huge\mathrm{Answer:}

{\large{\boxed{\mathbb{\red{⟶ VALUE \: OF \: P = 5 }}}}}

\huge\mathrm{Explanation:}

\mathfrak\purple{Refer \: to \: the \: attachments! ♡♡}

\Large\mathbb{OR}

\sf\blue{Mean = 21.6}

\sf\red{Mean = \frac{ \sum fixi}{ \sum fi} }

\sf\green{=\frac{558+18p}{25+p} }

\mathbb\orange{THUS,}

\sf\purple{21.6 = \frac{558+18p}{25+p} }

\sf\blue{21.6 ( 25+p ) = 558 + 18p}

\sf\red{540+21.6p = 558+18p}

\sf\green{21.6p-18p = 558 -540}

\sf\orange{3.6p= 18}

\sf\purple{p = \cancel{18} \times \cancel{\frac{10}{36} } }

\large{\underline{\sf{Value \: of \: p = 5}}}

\huge\mathrm{ Verification : }

\sf{According \: To \: the \: Question :}

\sf{Mean = 21.6}

\sf{Value \:  of \: p = 5}

\sf{ With \: reference \: to \: the \: tabulation :}

\sf{\sum Fixi= 558 + 18p = 558 + 18 \times 5 = 558 + 90 = 648}

\sf{\sum fi = 25 + p = 25 + 5 = 30 }

\sf{Mean = \frac{\sum fixi }{\sum fi} }

\sf{Mean = \frac{648 }{30} }

\sf{Mean = 21.6 }

{\large{\boxed{\sf{21.6=21.6}}}}

{\large{\boxed{\bf{Thus,\: verified! :)}}}}

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