Find the value of following expressiom
sin ( 90-theta) cosec theta tan ( 90-theta) cot theta / 3 tan 27 tan 63
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Hi ,
1 )Sec ( 90 - A ) = cosecA
2 ) Tan( 90 - A ) = cot A
3 )Cos 25 = cos ( 90 - 65 ) = sin65
4 )Tan 27 = tan ( 90 - 63 ) = cot 63
5 ) cosec²A - cot² A = 1
6 ) sin² A + cos² A = 1
7 ) cotA tanA = 1
Now ,
Sec(90-A)cosecA - tan( 90-A)cotA+ cos² 25 + cos² 65/ 3tan27tan63
= CosecAcosecA - cotAcotA + sin²65+cos²65/3cot63tan63
=( Cosec² A - cot² A)+ ( sin²A+cos²A)/ 3cot63tan63
= ( 1 + 1 )/ 3
= 2/3
I hope this helps you.
:)
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