Question

Find the value of following without actual multiplication (3x-4y+z)(3x+4y-z)​

Answer 1

Answer:

it is the formula of (a-b) (a+b) so the answer is

${a}^{2} - {b}^{2}$

Answer 2

(3x-4y+z)(3x+4y-z)

={3x-(4y-z)}{3x+(4y-z)}

=(3x)²-(4y-z)²

=9y²-(16y²+z²-8yz)

=9y²-16y²-z²+8yz

= -7y²-z²+8yz

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