Find the value of for (√6)^x-2=1
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Step-by-step explanation:
(i)(
6
)
x−2
=1
6
(
2
x−2
)
=6
0
∴(
2
x−2
)=0
∴x=2
(ii)3
4x
=(
81
1
)
81x=81
−1
∴x=−1
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