Question

find the value of four trigonometic function of cos r =½,r lies in third quadrant​

Answer 1

Answer:

Step-by-step explanation:

cos r=1/2=Base/hypotenuse

So base=1

hypotenuse =2

So height=√2²-1²=√4-1= √3

In third quadrant  only cos and sec are positive others are negative

Hence sin r =- ht/hypo=- √3/2

tan r =-base/ht= -1/ √3

cot r=- √3

sec r=1/cosr=1/12=2

cosec r=- hyp/ht=-2/ √3