Find the value of frequencies X and y in the following frequency distribution table if n = 100 and median is 32
Answers
Answered by
6
Answer:
y =16
Explanation:
class f cf
0-10 10 10
10-20 x 10+x
20-30 25 35+x
30-40 30 65+x
40-50 y 65+x+y
50-60 10 75+x+y
75+x+y
75+x+y=100
x+y=25
f=30,h=10,cf=35+x,
2
n
=50
Median=l+(
f
2
n
−cf
)×h
32=(
30
50−35−x
)×10
32−30=
3
15−x
6=15−x
x=9
∴y=16
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