Question

Find the value of g at a height of 400 km above the surface of the earth . Given radius of the earth , R = 6400 km and value of g at the surface of the earth = 9.8 ms^(-2).

Answer 1

$\underline{\boxed{ \huge\purple{ \rm{Answer}}}} \\ \\ \implies \rm \: formula \: of \: g \: at \: height \: is \: given \: by... \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \star \: \underline{ \boxed{ \bold{ \rm{ \pink{g' = \frac{g}{ {(1 + \frac{h}{r}) }^{2} }}}}}} \: \star \\ \\ \dag \: \blue{ \mathfrak{calculation}} \\ \\ \implies \rm \: g' = \frac{9.8}{ {(1 + \frac{400}{6400} )}^{2} } \\ \\ \therefore \rm \: g' = \frac{9.8}{ {(1 + \frac{1}{16}) }^{2} } = \frac{9.8}{ {1.0625}^{2} } \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \orange{g' = 8.68 \: \frac{m}{ {s}^{2}}}}}} }$

Answer 2

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