find the value of g at a height of 400km above the surface of the earth R=6400,g=9.8m/s
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Find the value of g at a height of 400 km above the surface of the earth . Given radius of the earth , R = 6400 km and value of g at the surface of the earth = 9.8ms –²
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M = 6×10^24kg
R =6400 km
= 6400×1000 =6.4×10^6 m
h = 400 km
= 400×1000 m
= 4×10^5 m
g=GM/(R+h)^2
= (6.67×10^-11 × 6×10^24)/ (6.4×10^6+4×10^5)
= (40.02×10^13)/(6.4+0.4)×10^6
= (40.02/6.8)×10^7
= 5.88×10^7 N.
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