Question

find the value of 'g' at a height of 800 km above the surface of earth.
Given - Radius of earth= 6400km,
g =9.8ms-2
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Answer 1

Answer:

value of g = 9.8ms-²

..hope it help you.

Answer 2

Answer :-

$\sf Given \begin{cases} & \sf{h = 800 km} \\ & \sf{R_e = 6400} \\ & \sf{g = 9.8 ms^{-2}}\end{cases}$

To find :-

Value of acceleration due to gravity

Solution :-

$\sf g' = \dfrac{g}{\big(1 + { \dfrac{h}{R_e} }\big)^{2} }$

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Substituting the value in formula :-

➩ $\sf g' = \dfrac{9.8}{\big(1 + { \frac{\cancel{800}}{\cancel{6400}} }\big)^{2} }$

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➩ $\sf g' = \dfrac{9.8}{\big(1 + { \dfrac{1}{8} }\big)^{2} }$

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➩ $\sf g' = \dfrac{9.8}{\big( { \dfrac{9}{8} }\big)^{2} }$

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➩ $\sf g' = \dfrac{9.8}{\big(\dfrac{81}{64}\big)}$

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➩ $\sf g' = \dfrac{9.8 \times 64}{81}$

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➩ $\sf g' = 7.74$

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Acceleration due to gravity = 7.74 m/s²