Question

Find the value of g at the height of 2R
Solution

Answer 1

Answer:

1.089 m/s²

Explanation:

When the object is taken at a height of 'h' above the surface of the Earth, then it will be at a distance r = R + h from the centre of the Earth. Hence acceleration due to gravity at height h is

$g_{h}$ = $\frac{GM}{(R + h)^{2}}$

Given that h = 2R (in question),

$g_{2R}$ = $\frac{GM}{(2R + R)^{2}}$

⇒ $g_{2R}$ = $\frac{1}{9} \frac{GM}{R^{2}}$

⇒ $g_{2R}$ = g/9

Which is approximately 1.089 m/s²

Thanks !