Question

Find the value of g'= g(1-2/291) ^ 1/2

Answer 1

Answer:

g' = 290g/291

Step-by-step explanation:

Given that,

g' = g ( 1 - 2/291)^1/2

We can also write above equations as:

g' = g ( 1 + (-2/291)^1/2

Using Bionmial Theorem,

When |x|<<1,

Then ( 1 + x )^n = 1 + nx

So,

g'= g ( 1 + 1/2 * -2/291)

  = g ( 1 - 1/291 )

  = g ( 290/291 )

Therefore,

g' = 290g/291