find the value of given that k k+5,5k are in ap
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2k+1,13 and 5k−3 are three consecutive terms of an A.P
Then, difference of first two terms is same as the difference of next two terms
∴ 13−(2k+1)=(5k−3)−13
⟹ 13−2k−1=5k−3−13
⟹ 12−2k=5k−16
⟹ 28=7k
∴ k=4
[tex][/tex]
Answered by
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Answer:
Step-by-step explanation:
5k-(k+5) = k+5-k
5k-k-5 = 5
4k = 10
k= 10/4
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