Question

find the value of h if (h+3)x^2-(11h+1)x+h-2(h-5)=0

Answer 1

Answer:

Solution

Let us consider reaction (i) and (ii)

Multiplying reaction (i) by 2, we get.

2H2(g)+2CO2(g)⇔2H2O(g)+2CO(g) ...(iv)

K

II

2000K

=K

2

2000K

=(4.40)2

Adding (iv) and (ii), we have

2CO2(g)⇔2CO+O2

K

III

2000K

=K

II

2000K

×K

I

2000K

=(4.40)2×5.31×10-10

Therefore, by reversing the reaction, we get reaction (iii) but at 2000K.

2CO(g)+O2(g)⇔2CO2(g), for which,

K

IV

2000K

=

1

K

III

2000K

=

1

4.402×5.31×10-10

=9.72×107

From reactions (iii) and (v), we see that as the temperature increases, the equilibrium constant decreases (9.72×107<2.24×1022). Reaction (iii) is this exothermic because ΔH will be negative.