Find the value of h if tje distance between (h,3) and (4,5) is 5
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Using distance formula
d= sqrt((X2-X1)^2+(Y2-Y1)^2)
5=sqrt((4-h)^2+(5-3)^2)
5=sqrt((4-h)^2+2^2)
5=sqrt((4-h)^2+4)
Squaring both sides
25=(4-h)^2+4
(4-h)^2=21
4-h=sqrt(21)
h=4-sqrt(21)
d= sqrt((X2-X1)^2+(Y2-Y1)^2)
5=sqrt((4-h)^2+(5-3)^2)
5=sqrt((4-h)^2+2^2)
5=sqrt((4-h)^2+4)
Squaring both sides
25=(4-h)^2+4
(4-h)^2=21
4-h=sqrt(21)
h=4-sqrt(21)
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