FIND THE VALUE OF H
SUCH THAT 2M JUST MANAGES TO RISE ABOVE GROUND AFTER COLLISION
?
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Hydrogen increases by .69
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Answer:h=4mg/K
Explanation:Kinetic energy of 2m becomes zero after collision and kinetic energy of m will be converted into potential energy mgh and that will be equal to sum of potential energy due to rise of m and potential energy of spring 1/2 (kx^2)
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