Question

find the value of:-
i) (1/-5)⁸
ii) (-3/11)⁴​
iii) (1/9)⁵

Answer 1

Answer:

The values are as follows

i) (1/-5)⁸= (1/390625)

ii)(-3/11)⁴=(81/14641)

iii)(1/9)⁵=(1/59049)

Step-by-step explanation:

01. $(\frac{1}{-5} )^{8}$=$\frac{1}{-5}$×$\frac{1}{-5}$×$\frac{1}{-5}$×$\frac{1}{-5}$×$\frac{1}{-5}$×$\frac{1}{-5}$×$\frac{1}{-5}$×$\frac{1}{-5}$

⇒ $(\frac{1}{-5} )^{8}$=$\frac{1}{25}$×$\frac{1}{25}$×$\frac{1}{25}$×$\frac{1}{25}$

⇒ $(\frac{1}{-5} )^{8}$=$\frac{1}{625}$×$\frac{1}{625}$

⇒ $(\frac{1}{-5} )^{8}$=$\frac{1}{390625}$

02.$(\frac{-3}{11} )^{4}$= $\frac{-3}{11}$×$\frac{-3}{11}$×$\frac{-3}{11}$×$\frac{-3}{11}$

⇒$(\frac{-3}{11} )^{4}$=$\frac{9}{121}$×$\frac{9}{121}$

⇒$(\frac{-3}{11} )^{4}$=$\frac{81}{14641}$

03.$(\frac{1}{9})^{5}$ =$\frac{1}{9}$×$\frac{1}{9}$×$\frac{1}{9}$×$\frac{1}{9}$×$\frac{1}{9}$

⇒$(\frac{1}{9})^{5}$ = $\frac{1}{81}$×$\frac{1}{81}$×$\frac{1}{9}$

⇒$(\frac{1}{9})^{5}$ =$\frac{1}{6561}$×$\frac{1}{9}$

⇒$(\frac{1}{9})^{5}$ =$\frac{1}{59049}$

Answer 2

Answer:

see the attachment

hope it help you

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