Math, asked by agnishasumellikalove, 2 months ago

find the value of:-
i) (1/-5)⁸
ii) (-3/11)⁴​
iii) (1/9)⁵

Answers

Answered by shabeehajabin
2

Answer:

The values are as follows

i) (1/-5)⁸= (1/390625)

ii)(-3/11)⁴=(81/14641)

iii)(1/9)⁵=(1/59049)

Step-by-step explanation:

01. (\frac{1}{-5} )^{8}=\frac{1}{-5}×\frac{1}{-5}×\frac{1}{-5}×\frac{1}{-5}×\frac{1}{-5}×\frac{1}{-5}×\frac{1}{-5}×\frac{1}{-5}

(\frac{1}{-5} )^{8}=\frac{1}{25}×\frac{1}{25}×\frac{1}{25}×\frac{1}{25}

(\frac{1}{-5} )^{8}=\frac{1}{625}×\frac{1}{625}

(\frac{1}{-5} )^{8}=\frac{1}{390625}

02.(\frac{-3}{11} )^{4}= \frac{-3}{11}×\frac{-3}{11}×\frac{-3}{11}×\frac{-3}{11}

(\frac{-3}{11} )^{4}=\frac{9}{121}×\frac{9}{121}

(\frac{-3}{11} )^{4}=\frac{81}{14641}

03.(\frac{1}{9})^{5} =\frac{1}{9}×\frac{1}{9}×\frac{1}{9}×\frac{1}{9}×\frac{1}{9}

(\frac{1}{9})^{5} = \frac{1}{81}×\frac{1}{81}×\frac{1}{9}

(\frac{1}{9})^{5} =\frac{1}{6561}×\frac{1}{9}

(\frac{1}{9})^{5} =\frac{1}{59049}

Answered by tulikasharma2018
2

Answer:

see the attachment

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