Math, asked by pratikshakesharwani8, 10 days ago

find the value of .i. 16 power -3/4​

Answers

Answered by ItsRuchikahere
2

 {16}^{   (- \frac{3}{2}) }  =  \frac{1}{ \sqrt{ {16}^{3} } }  =  \frac{1}{ \sqrt{ 4096}}  \\  =  \frac{1}{64}  \\  \boxed{  \orange{ \sf \: {16}^{   (- \frac{3}{2}) =  \frac{1}{64}  }}}

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