Question

find the value of i-³⁵​

Answer 1

Answer:

i⁻³⁵

=i⁻³⁴⁻¹

=(i²)⁻¹⁷×(i⁻¹)

=(-1)⁻¹⁷(1/i)

=1/(-1)¹⁷(1/i)

=(-1)(1/i)

=-1/i

=0+i(-1/i²)

=0+i(-1/-1)

=0+i.1

where a=0, b=1

Answer 2

${i}^{ - 35} \\ = {({i}^{4} )}^{8}. {i}^{3}\\= 1. {i}^{3} \\ = {i}^{2} .i \\ = - 1.i \\ = - i$

Since i^4 = 1

i^2 = -1