Find the value of:
(i) 36x2 + 49y2 + 84xy, when x = 3, y = 6
(ii) 25x2 + 16y2 – 40xy, when x = 6, y = 7
Answers
Answered by
2
Answer:
1. 36×3×2 + 49×6×2 + 84×3×6
216 + 588 + 1512
=2316
2. 25×6×2 + 16×7×2-49×6×7
300 + 224 - 2058
= -1534
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Answered by
1
Answer:
(i) Substituting the value of x and y
36(3)² + 49(6)² + 84(3)(6)
= 36(27) + 49(36) + 84(18)
= 972 + 1764 + 1512
= 4248
(ii) Substituting the value of x and y
25(6)² + 16(7)² - 40(6)(7)
= 25(36) + 16(49) - 40(42)
= 900 + 784 - 1680
= -4
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