find the value of i^57 + 1/ i^125
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Answered by
18
i^57 + 1/ i^125
= I * I^56 + 1/ I * i^124
= I * {(I)^4}^14 + 1 / I * {(I)^4}^31
Now as we know that- ( I)^4 =1
so, I + 1/I =( I^2+1)/I
since I ^2 = -1
hence ( I^2+1)/I = 0 ans
= I * I^56 + 1/ I * i^124
= I * {(I)^4}^14 + 1 / I * {(I)^4}^31
Now as we know that- ( I)^4 =1
so, I + 1/I =( I^2+1)/I
since I ^2 = -1
hence ( I^2+1)/I = 0 ans
Answered by
14
we know (i)^4n=1 where n is natural number
now i^57=i^(4*14+1)=(i^4*14).i=i
i^125=i^(4.31+1)=(i^4*31).i=i
also we know 1/i =-i
so, i^57+1/i^125=0
now i^57=i^(4*14+1)=(i^4*14).i=i
i^125=i^(4.31+1)=(i^4*31).i=i
also we know 1/i =-i
so, i^57+1/i^125=0
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