Question

find the value of i^93

Answer 1

Heya!

Here is your answer:

${i}^{93}$

$= i \times {i}^{92}$

$i \times { ({i}^{2})}^{46}$

$we \: know \: that \\ \: {i}^{2} = - 1$

$i \times { ({ - 1})}^{46}$

$i \times 1$

$= i$

Answer 2

${i}^{93} \\ \\ = {i}^{1 + 92} \\ \\ = i \times {i}^{92} \\ \\ = i \times {i}^{4 \times 23} \\ \\ = i \times {( {i}^{4} )}^{23} \\ \\ = i \times {1}^{23} \\ \\ = i \\ \\ = \sqrt{ - 1}$

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