Math, asked by Abighaya, 6 months ago

Find the value of
(i) 9x2 + 49y2 + 42xy, when x = 3, y = 1
9
(ii) 4x2 + -12, when x = 2
2
2​

Answers

Answered by kothwalshreya
0

9 9 x 2 + 49 by 2 + 42 x y is equals to x is equals to 3 y is equals to 19 into 2 + 49 into one into 2 + 42 into 3 into 1 is equals to 49 into two plus 42 into 349 into 2 + 42 into 3 is equals to 49 + 42 is equals to 3 + 3 + 2 is equals to 55 is equals to 49 + 42 1449 + 42 divided by 5 is equals to the answer is 2

Answered by Vibhav077
1

Answer:

I answer = 256

ii answer =16-12=4

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